We have some hoops (the sort you hula with). I don't like to hula, I prefer throwing them, and using back spin, make them come back. I know how/why this works, but I find it "curious" and think of nothing, of just doing this over and over, seing how far I can make it travel, before stopping, and then coming back to me, and going past me in the other direction.
Now, my garden is essentially a patio on 2 levels, with a ledge seperating them, forming a double step type thing:
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If, I stand on the bottom level, I can throw the hoop onto the top level, have it spin back, and roll on to the lower level again. Sometimes, it hits the middle step on the way done, sometimes it doesn't. I want to know the speed it needs to be travelling at (assuming it's rolling and not bouncing) as it leaves the top level to not hit the middle step.
This is the first question, I guess you are going to need some measurements, The difference in height between the 2 levels is 80cm, the step is 50cm heigh and 60cm deep, so the question is how fast does the hoop need to be travelling horizontally (V
x) to clear 60cm horizontally before dropping 30cm vertically?
Now, I can work that out myself (along with the next part), so I'll be checking answers later.
Part 2 is to work out the "general case" with the height of the step is "h", the depth of the step is "d" and the height of the upper patio is "u"
Part 3 is beyond me at the moment, so this is where I need the real help. I want to know how fast I need to throw this in the first place. I guess there are 5 variables here.
1) The height of release (r)
2) The angle of release (a)
3) The speed of release (v)
4) The RPM of the hoop at release (f)
5) The coefficient of dynamic friction between the hoop and patio
Am I missing anything? Can anyone work out some solutions on how I need to throw the hoop for it come back to without hitting that middle step? What about the "general case"?
Thanks
Malc